Volume Displacement ```Name: Unknown Status: N/A Age: N/A Location: N/A Country: N/A Date: Around 1993 ``` Question: If you were in a boat in a small swimming pool (so that you could measure the water level) and there were rocks in the boat, What would happen to the water level if you threw the rocks into the water? Would it rise, lower, or remain the same level as when the rocks were in the boat? Replies: Let us note in passing that since each rock sinks, each rock's overall density must be greater than that of water. When a rock is in the boat, Archimedes' principle tells us that the weight of the volume of water displaced due to that rock is equal to the weight of the rock. Since the rock is denser than water, this displaced volume of water is larger than the volume of the rock (weight = mass density times volume times g, the acceleration due to gravity). But when the rock is on the bottom of the pool, it merely displaces a volume of water equal to the rock's volume. Hence, more water is displaced when the rock is in the boat than when the rock is on the pool bottom. Therefore, the water level will drop each time a rock is thrown out of the boat into the water. R.C. Winther Click here to return to the Physics Archives

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