Last Ionization Energy
I have encountered a question from a science contest test
that has me stumped. I contend that there is not
How much energy is required to remove the last electron
from the Boron+4 ion?
That is it! The answer key says the answer is 321 ev.
Without knowing the distance between the electron and the
Nucleus I can not see a solution. Any Ideas?
It is quite simple. Boron +4 has a hydrogen like electronic
structure because there is only one electron. So you can do the same
calculation as for a hydrogen atom but with a different charge on the nucleus.
Yup. What they did not say was that the system was in
its lowest energy state, but you can usually assume that sort
of thing. Just multiply the Rydberg (the ionization energy of
Hydrogen) by 25 to get the ionization energy for Boron...
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Update: June 2012