Non-Simultaneous Drop of Objects ```Name: Sky Status: student Grade: 9-12 Country: South Africa Date: Summer 2011 ``` Question: At school, my teacher and I are having a debate about a question that was asked recently. It goes as follows: Two identical objects are dropped 1 second apart in a vacuum does the distance between them: A: Remain the same B: Increase C: Decrease I believe that the distance will increase, but she is extremely confident that it will in fact remain the same. Would you please give me an explanation? Thanks so much. Sky Replies: Hi Sky, You are right Sky. To convince your teacher you should prepare a spreadsheet table that is based on the equation s = 1/2 a * t^2. In the equation s is the distance a object would travel with an acceleration a (earth's gravity effect of 32 ft / sec^2) and t is the time. Your table should show the time for each object falling, with one object starting one second behind. At each second interval compute and compare the distance s. The table will clearly show you are correct. Carlton Schroeder Click here to return to the Physics Archives

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