Shunts in Ammeters ```Name: Austin Status: student Age: N/A Location: N/A Country: N/A Date: N/A ``` Question: In electrical measurement, can somebody please explain to me why an ammeter requires an internal shunt, but a voltmeter does not? Replies: Austin - A volt meter is rather high in resistance and only a small current travels through the meter itself. It is used in parallel ... meaning that it is not the only path for the current. An ammeter is used in series to measure the current flow in a particular circuit. It must provide a path for the entire current. It would be difficult to develop a meter that would handle significant amounts of current. With that in mind, the ammeter uses a shunt to allow some of the current to travel through a course parallel to the meter. If the shunt malfunctions, it is likely the meter will not be able to handle the current. Larry Krengel Voltmeters and ammeters typically have a similar problem: the sensing unit has a smaller sensing range than is desired. To extend the range, you add circuits that adjust the voltage or current to be within the sensor's range. To understand why a shunt is used in an ammeter but not a voltmeter, you need to understand Ohm's law, and how it differs between serial and parallel circuits. In the case of voltmeters, you are trying to reduce the voltage, but not the current, so you can add a resistor in series. Voltmeters typically have several circuits (different resistors) to allow reading voltages across a very wide range. For an ammeter, to adjust current instead of voltage, you do not use an in-line resistor, but a parallel resistor. With a resistor in parallel, the current is split, but the voltage is the same. This parallel resistor is the 'shunt'. For more information, and a more detailed explanation, this site is very good: Ammeter: http://www.allaboutcircuits.com/vol_1/chpt_8/4.html Voltmeter: http://www.allaboutcircuits.com/vol_1/chpt_8/2.html Hope this helps, Burr Zimmerman Hi Austin An ideal voltmeter measures the potential difference (voltage) between two points and it has an infinitely high internal resistance so there would be no current flow through the voltmeter. In that way, the voltmeter can be used to probe a circuit without it affecting the operation of the circuit. An ideal ammeter has zero resistance so current can flow directly through the meter, unimpeded. Furthermore, from Ohm's law, V=IR (V is voltage, R is resistance and I is current) if resistance is zero, the voltage across the ammeter will also be zero. This way the ammeter can be inserted into a current path, current will flow through it like it was just a piece of wire, and it will not affect the voltage distribution in the circuit. Okay, those are ideal voltmeters and ammeters, but nothing is really ideal. So let us make a real ammeter out of a voltmeter. Because of Ohm's law, we can use a voltmeter to indicate current just by measuring the voltage present across a resistor (If we know V and we know R, we can calculate I). In a setup like this, the resistor we measure across must be very small - that is, current flows through it very easily - and that resistor is called a shunt. Since V=IR, if R is very small, for any value of I, V will be very small. In order to read that voltage, you will need a very sensitive voltmeter. Put the sensitive voltmeter together with a shunt and you have an ammeter. All you need to do now is to change the scale on the voltmeter from volts to amps following Ohm's law solved for current, I=V/R. Hope this helps! Bob Froehlich A voltmeter is in series (usually) with the power source. Inside the voltmeter is a resistor of known number of ohms and this is the "voltage" you read. If the voltage is high the voltmeter may contain an internal shunt in parallel, to "siphon off" the large share of the electrical current. In the case of an ammeter, the shunt in parallel with the ammeter (which also may be measuring the voltage drop across a resistor) is necessary because in an ammeter the current is typically too large, and several amps may "blow" the internal circuitry. Therefore it is more important to have a shunt resistor(s) in parallel with the meter to "siphon off" the large share of the electric current. Vince Calder Austin, An ammeter requires an internal shunt and a voltmeter requires an internal resistor. Quite often this resistor is already part of the voltmeter. Actually, a shunt is just a VERY SMALL resistor. Every ammeter and voltmeter has a coil or semiconductor device that has its own internal resistance. This internal device cannot handle a large current. To keep the current down, the voltage across this internal device must be kept fairly small. An ammeter, once structured, needs a VERY SMALL resistance, with almost no current flowing through the internal device. The easiest way to accomplish this is to put the internal device in parallel with a VERY SMALL resistor, a shunt. A large resistor in parallel with a small resistor has a very small resistance. Almost all current will flow through the shunt. When in series with a circuit object, such as a light bulb, the ammeter has full current (through the shunt) and very small voltage. It does not affect the rest of the circuit. Changing the shunt resistance can change the scale of the ammeter. A voltmeter, once structured, needs a VERY LARGE resistance, with almost no current flowing through the internal device. The easiest way to accomplish this is to put the internal device in series with a VERY LARGE resistor. A large resistor in series with a small resistor has a large resistance. When in parallel with a circuit object, such as a light bulb, the ammeter has full voltage (most of it across the large resistor) and very small current. IT does not affect the rest of the circuit. Change the large resistor can change the scale of the voltmeter. Dr. Ken Mellendorf Physics Instructor Illinois Central College Both ammeters and voltmeters use coils that respond to a voltage. They are typically capable of withstanding only millivolts of voltage difference between the terminals, and can tolerate only tiny currents within the coils of the meter movement. You could make a meter movement that would allow large current to flow through it, but it would be enormous. So how do you use a small meter movement to measure, say, 500 Amps of current? the answer in found in Ohm's law, which states that the voltage across an element is equal to the current flowing through it multiplied by the resistance (V=I*R). If we place a very small resistance in the circuit, with a value we know fairly accurately, we can measure the current flowing in the circuit by placing the leads of the meter on either side of the resistance we added. The resistor is in parallel with the meter. The resistors used for such purposes are called shunts. A typical shunt value is 500 Amps and 50 milliVolts. This means that there will be 50 milliVolts across the shunt when 500 amps are flowing through it. So a small 50 milliVolt meter movement can be used to measure a very large current. Shunts such as this are pretty big, so the ones used in small hand held meters are typically smaller, about 10 Amps. To use the same meter movement to measure a voltage, we connect a high resistance in series with the movement, so that even though we connect a large voltage to it, the current through the meter movement will be limited. Hand held meters use the dial to select a variety of resistors to allow the meter to measure different ranges of voltages. David Brandt Hi Austin. In that last several decades, we tend to make just one kind of meter element, or meter-core, around which we place voltage-dividers or current-shunt resistors to get it to read the right thing. After all, everybody wants a different meter. Or thirty different meters in one little box, for multi-meters. Suppose all meter-cores are purely voltage-sensitive. Then we need a "dropping resistor" (the shunt resistor) so our current will cause a certain amount of voltage-drop that our meter will read properly. It is not really true; a mechanical meter-core is often around 20-60 ohms and needs maybe 1mA at 20-60mV to deflect to the top of its scale. It requires both voltage and current. In practice their manufactured sensitivity varies a little, and is usually adjusted to some exact value by putting a largish resistor in series, which makes them a bit more voltage-like, maybe 1mA at 0.100v , which is 100 ohms. Or even 1mA at 1.00v, which is 1000 ohms. Digital electronic meter-cores are definitely purely voltage-sensitive; the FET transistors inside draw less than 1 millionth of an amp from the wires being measured. So meter-circuitry using them is easier to figure out. Either way, a current-meter needs to be a much lower resistance. So we get a low-value resistor and put one of our voltage-sensitive meter-cores across it. If we have a meter-core that needs 0.100v to go to full-scale, and we want 1.00 Amp to push it to full-scale, we need an 0.1-ohm shunt resistor. V = I x R 0.1v = 1Amp x 0.1 ohm With algebra you can turn it around any way that makes sense, such as: we know we have an 0.1v meter and want to measure 1 Amp, but we need a formula to tell use what shunt resistor to use. V = I x R can be changed to V/I => R to tell us directly. 0.10v / 1.0 A => 0.1 ohm I do this all the time in my lab. If your current-meter does not have a low-enough resistance, two problems can happen: 1) the voltage it takes up is a significant part of the voltage in the circuit you are measuring, so your ammeter actually starts choking down the current a little. This is considered a yucky inaccuracy even if it is only 10% current reduction. (Possibly you would not be so picky.) So we would not use a 1-volt meter core to make an ammeter to use on 12v cars. It would have to be an 0.1v meter core. Or less, if we like. 2) the resistor can get too hot and burn up. P = I x V 10 amps x 1 volt = 10 watts This means If you try to measure headlight current draw using a 1-volt meter core and the right 0.1-ohm resistor, that resistor has to also be pretty big, a "power resistor" we call it. But if you use an 0.10volt meter core, the right resistor is smaller, only 0.01 ohms and P = I x V: 10 amps x 0.10 volt = 1 Watt. A fairly small resistor can do it, and will not get hot enough to burn itself out or hurt when touched. So we have two good reasons to use a low-voltage meter core (0.1v or less). And being a voltmeter inside, it needs a current-shunt resistor to make it a current-meter. Meter-cores that are primarily current-sensitive can exist, sure. A wire carrying your current, passing a tiny bar-magnet on spring-bearings, with needle sticking out to a scale, would be a current-sensitive meter-core, and maybe it was made many years ago. A magnetic compass kind of does this today, if you arrange it right with respect to the wire and the north pole. Digikey sells newer transistor-like devices that measure the magnetic field around a wire (which is proportional to current), which are gradually becoming popular too. Guess what, they output 0-5 volts that goes to your favorite, uh, VOLTmeter. DC amp-clamps are part of this trend. Slowly they are getting cheap (<\$50). They do not involve current-shunt resistors, and you will not have to figure out what is inside if you do not want to. You do not even have to break open the measured circuit to put it through your ammeter; that is great... But so far, not having one on hand, most people still use shunt resistors and voltmeters. By the way, almost all voltmeters use voltage-dividers inside, made of two or more resistors, to get them to read the right full-scale range. They are not really simpler, just more likely pre-packaged in the box. And they are harder to burn out, so they need less education of their user. It is a pretty broad philosophical essay to explain why we have liked voltage more than current. I am sure some of our favorite electronic devices have something to do with it. Jim Swenson Click here to return to the Physics Archives

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