Sodium Hydroxide and Sulfuric Acid
Date: October 2006
In a neutralization reaction of NaOH and H2SO4,
because there are 2 acidic Hydrogens do you multiply the number of moles
Right, Kerry, presuming you neutralize all the way to pH=7 or maybe 9.
You can see the "2" in the reaction formula:
H2SO4 + 2 NaOH --> Na2SO4 +2 H2O
Na2SO4 will by slightly basic, hence the pH 9.
If you stopped at pH=5, the reaction would be
H2SO4 + NaOH --> NaHSO4 + H2O
and the mole ratio would be 1.
NaHSO4 is the "bi-sulfate".
Somewhere around pH=6-8,
the reaction of bisulfate to sulfate would be roughly half done,
and if you stopped near that pH
the mole ratio would appear to be a non-integer between 1 and 2.
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Update: June 2012